Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
58 views
in Aptitude by (111k points)
closed by

In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.

I. x2 – 20x + 91 = 0

II. y2 + 6y – 91 = 0


1. x < y
2. x > y
3. x ≤ y
4. x ≥ y
5. x = y or the relation between x and y can't be established.

1 Answer

0 votes
by (105k points)
selected by
 
Best answer
Correct Answer - Option 4 : x ≥ y

Calculation:

I. x2 – 20x + 91 = 0

⇒ x– 13x – 7x + 91 = 0

⇒ x(x – 13) – 7(x – 13)= 0

⇒ (x – 13)(x – 7) = 0

⇒ x = 13, 7

II. y2 + 6y – 91 = 0

⇒ y+ 13y – 7y – 91 = 0

⇒ y(y + 13) – 7(y + 13) =0

⇒ (y + 13)(y – 7) = 0

⇒ y = 7, (-13)

Value of ‘x’

Relation

Value of ‘y’

13

7

13

-13

7

=

7

7

>

-13


When we compared the values of ‘x’ and ‘y’ in the table above, we found that there is TWO relations between X and Y i.e. > and =. So, a relation between x and y is “x ≥ y”.

 After comparison, all the values of x and y the relation is “x  y”.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...