Correct Answer - Option 4 :
x ≥ y
Calculation:
I. x2 – 29x + 54 = 0
⇒ x2 – 27x – 2x + 54 = 0
⇒ x(x – 27) – 2(x – 27)= 0
⇒ (x – 27)(x – 2) = 0
⇒ x = 27, 2
II. y2 + 28y – 60 = 0
⇒ y2 + 30y – 2y – 60 = 0
⇒ y(y + 30) – 2(y – 30) =0
⇒ (y + 30)(y – 2) = 0
⇒ y = (-30), 2
Comparison between x and y (via Tabulation):
Value of ‘x’
|
Relation
|
Value of ‘y’
|
27
|
>
|
-30
|
27
|
>
|
2
|
2
|
>
|
-30
|
2
|
=
|
2
|
When we compared the values of ‘x’ and ‘y’ in the table above, we found that there is TWO relations between X and Y i.e. > and =. So, a relation between x and y is “x ≥ y”.
∴ After comparison, all the values of x and y the relation is “x ≥ y”.