Correct Answer - Option 3 :
x ≤ y
Calculation:
I. x2 – 25x + 46 = 0
⇒ x2 – 23x – 2x + 46 = 0
⇒ x(x – 23) – 2(x – 23)= 0
⇒ (x – 23)(x – 2) = 0
⇒ x = 23, 2
II. y2 – 46y + 529 = 0
⇒ y2 – 23y – 23y + 529 = 0
⇒ y(y – 23) – 23(y – 23) =0
⇒ (y – 23)(y – 23) = 0
⇒ y = 23, 23
Value of ‘x’
|
Relation
|
Value of ‘y’
|
23
|
=
|
23
|
2
|
<
|
23
|
When we compared the values of ‘x’ and ‘y’ in the table above, we found that there are TWO relations between X and Y i.e. < and =. So, a relation between x and y is “x ≤ y”.
∴ After comparison, for all the values of x and y the relation is “x ≤ y”.