Correct Answer - Option 4 : 960
Given:
A person walks 20 km/h slower than his usual speed, he takes 4 hours more to cover a certain distance
He walks 40 km/hr faster than his usual speed, he takes 4 hours less to cover that distance.
Formula used:
Time = Distance/Speed
Speed = Distance/Time
Calculation:
Let the original speed be m km/h and the distance is x km
For the first case get,
x/(m - 20) - x/m = 4
⇒ x[(m - m + 20)]/m(m - 20) = 4
⇒ x = m(m - 20)/5 ----(1)
Again from the 2nd case get,
x/m - x/(m + 40) = 4
⇒ x(m + 40 - m)/m(m + 40) = 4
⇒ 40x/m(m + 40) = 4
⇒ x = m(m + 40)/10 ----(2)
From (1) and (2) get,
m(m - 20)/5 = m(m + 40)/10
⇒ 5m + 200m = 10m - 200
⇒ -5m = -400
⇒ m = 80
Original speed = 80 km/hr
Now, from equation(1),
x/(m - 20) - x/m = 4
⇒ x/(80 - 20) - x/80 = 4
⇒ x/60 - x/80 = 4
⇒ (4x - 3x)/240 = 4
⇒ x/240 = 4
⇒ x = 960
∴ The distance (in km) is 960.