Correct Answer - Option 1 : 232
Given:
Per cent of passed students in Mathematics = 65%
Per cent of passed students in Physics = 75%
Failed in both the subjects = 18%
The total number of students is 400
Concept used:
(A ∪ B) = (A) + (B) – (A ∩ B)
(A ∪ B) → Total
(A) → Part of A
(B) → Part of B
(A ∩ B) → The common part of A and B
Calculations:
The number of students passed in at least one subject = 100 - 18 = 82%
Students passed in at least one subject (A ∪ B) = 82%
Students passed in Mathematics (A) = 65%
Students passed in Physics (B) = 75%
Students passed in both subjects = (A ∪ B)
82% = 65% + 75% - (A ∪ B)
⇒ (A ∪ B) = 140% - 82% = 58%
Now, 58% of 400 students
400 × (58/100) = 232
∴ The number of students passed in both subjects is 232.