Correct Answer - Option 1 : 25
\(\dfrac{(5^4)^{6.25}\times(5^2)^{2.6}}{(5^4)^{6.75}\times(5^{1/2})^{2.4}}\times\dfrac{(0.7^2)^4\times(0.7^3)^4}{(0.7^4)^5}\)
\(\dfrac{(5^{25})\times(5^{5.2})}{(5^{27})\times(5^{1.2})}\times\dfrac{(0.7^8)\times(0.7^{12})}{(0.7^{20})}\)
\({(5^{25 +5.2-27-1.2})}\times{(0.7^{8+12-20})}\)
\({(5^2)}\times{(0.7^0)}\)
= 25