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The HCF of two numbers is 24. If sum of the numbers is 480, how many such pairs of numbers are possible?
1. 2
2. 5
3. 4
4. 3

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Correct Answer - Option 3 : 4

Given:

HCF = 24

Sum of two number = 480

Concept used:

If the number is 24a and 24b, then a and b will be prime number

Calculation:

Let the number be 24a and 24b

24a + 24b = 480

⇒ 24(a + b) = 480

⇒ a + b = 20

Now, the required possible pair of values of a and b which are common numbers to each other are (1, 19), (3, 17), (7, 13), (9, 11)

∴ There will be 4 possible pairs.

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