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If σ is the conductivity, What is the relation between the electric field E and the current density J in a conducting medium?
1. σ = J/E
2. σ = 1/JE
3. σ = E/J
4. σ = EJ

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Correct Answer - Option 1 : σ = J/E

Concept:

Ohms’ law: At constant temperature, the current through a resistance is directly proportional to the potential difference across the resistance.

V = R I

Where V is the potential difference, R is resistance and I is current flowing

Current density (J): The electric current per unit area is called current density.

\(Current~density~\left( J \right)=\frac{Current~\left( I \right)}{Area~\left( A \right)}\)

Conductivity (σ): The property of a conductor due to which the current flows through it is called the conductivity of that conductor.

\(Resistance~\left( R \right)=\frac{\rho ~l}{A}\)

Where ρ is resistivity = 1/σ, l is the length and A is the area of the conductor

Electric field (E) = potential difference (V)/length (l)

Analysis:

As, V = R I 

\(Resistance~\left( R \right)=\frac{\rho ~l}{A}\)

\(V=\frac{\rho ~l}{A}\times I=\left( \frac{1}{σ } \right)\times l\times \frac{I}{A}=\left( \frac{1}{σ } \right)\times l\times J\)

\(J=σ \times \frac{V}{l}=σ ~E\)

σ = J/E

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