Correct Answer - Option 3 : 0.87
Concept:
\(kinematic~ viscosity= \frac {dynamic ~ viscocity}{density ~of ~fluid}\)
\(ν = \frac {μ}{ρ }\)
density = specific gravity × 1000
Calculation:
Given:
μ = 0.7 poise = 0.07 kg/ms, specific gravity = 0.8,
∴ ρ = 0.8 × 1000 = 800 kg/m3
\(ν = \frac {μ}{ρ }\)
\(ν = \frac {0.07}{800}=0.87 \times 10^{-4}=0.87 \) stokes