Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
50 views
in Aptitude by (114k points)
closed by
In ΔABC, AB = 6√3 cm, AC = 12 cm and BC = 6 cm, then ∠B is
1. 120°
2. 60°
3. 90°
4. 45°

1 Answer

0 votes
by (113k points)
selected by
 
Best answer
Correct Answer - Option 3 : 90°

Given:

AB, BC and AC are the three sides of ΔABC of length 6√3 cm, 6 cm and 12 cm respectively

Concept used:

If in a ΔABC, AB2 + BC2 = AC2

Then ΔABC is a rightangle triangle with ∠B = 90°

Calculation:

According to the concept, we have

 AB2 + BC2 = {(6√3)2 + 62} cm2

⇒ (108 + 36) cm2

⇒ 144 cm2      ----(1)

And, AC2 = 12cm2

⇒ 144 cm2      ----(2)

Here, equation (1) = equation(2)

So, AB2 + BC2 = AC2

∴ ∠B is 90°.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...