Correct Answer - Option 2 : Zero
Concept:
KP = position error constant = \(\mathop {\lim }\limits_{s \to 0} G\left( s \right)H\left( s \right)\)
Kv = velocity error constant = \(\mathop {\lim }\limits_{s \to 0} sG\left( s \right)H\left( s \right)\)
Ka = acceleration error constant = \(\mathop {\lim }\limits_{s \to 0} {s^2}G\left( s \right)H\left( s \right)\)
Steady-state error for different inputs is given by
|
Input
|
Type -0
|
Type - 1
|
Type -2
|
|
Unit step
|
\(\frac{1}{{1 + {K_p}}}\)
|
0
|
0
|
|
Unit ramp
|
∞
|
\(\frac{1}{{{K_v}}}\)
|
0
|
|
Unit parabolic
|
∞
|
∞
|
\(\frac{1}{{{K_a}}}\)
|
From the above table, it is clear that for type – 1 system, a system shows zero steady-state error for step-input.
