Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
189 views
in Aptitude by (114k points)
closed by

The value of tan 16° + 2 + tan 16° cot 61° + 4(sin 41° cos 41°)/cos 8° + cot 61° is - 


1. 3
2. 8
3. 5
4. 4

1 Answer

0 votes
by (113k points)
selected by
 
Best answer
Correct Answer - Option 3 : 5

Given:

tan 16° + 2 + tan 16° cot 61° + 4(sin 41° cos 41°)/cos 8° + cot 61°

Formula Used:

When, x+ y = 45°

tan x + tan y + tan x tan y = 1

Calculation:

tan 16° + 2 + tan 16° cot 61° + 4(sin 41° cos 41°)/cos 8° + cot 61°

⇒ tan 16° + 2 + tan 16° cot(90° - 29°) + 2(2 sin 41° cos 41°)/cos 8° + cot(90° - 29°)

⇒ tan 16° + 2 + tan 16° tan 29° + 2(sin 82°)/cos 8° + tan 29°

⇒ (tan 16° + tan 29° + tan 16° tan 29°) + 2 + 2 sin(90°- 8°)/cos 8°

⇒ 1 + 2 + 2 cos 8°/cos 8°

⇒ 1 + 2 + 2

⇒ 5

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...