Correct Answer - Option 1 : 2√5
Given
Ratio of length of each equal side and third side of an isosceles triangle is 3 ∶ 4
Concept used
Area of an isosceles triangle = \(\frac{b}{4}\sqrt{4{a^2} - {b^2}} \)
Where a = same side, b = unequal side
Calculation
Here equal side (a = 3 cm)
Unequal side (b = 4 cm)
Area = \(\frac{b}{4}\sqrt{4{a^2} - {b^2}} \)
Area = \(\frac{4}{4}\sqrt{4 \times {3^2} - {4^2}} \)
Area = \(\sqrt{36 - 16} \)
Area = \(\sqrt{20} \)
Area = 2√5
