Correct Answer - Option 3 : 1993
Calculation:
For the non-leap year, number of odd days = 1
For leap year, number of odd days = 2
1988 is a leap year
If the number of odd days becomes zero then only the same day falls on that year
Number of odd days in the year 1988 = 2 days
Number of odd days in the year 1989 = 1 days
Number of odd days in the year 1990 = 1 days
Number of odd days in the year 1991 = 1 days
Number of odd days in the year 1992 = 2 days
The number of odd days from 1988 - 1992 = 2 + 1 + 1 + 1 + 2
⇒ 7 days
After completion of 7 days then only it will fall on same day
Hence 15th February fall on Monday after 1988 is 1993
∴ In the year 1993 February 15 is Monday
