Correct Answer - Option 1 : x > y
Given:
I. x2 – 23x + 132 = 0
II. y2 = (∛216)2
Calculation:
From I,
x2 – 23x + 132 = 0
⇒ x2 – 11x – 12x + 132 = 0
⇒ x(x – 11) – 12(x – 11) = 0
⇒ (x – 11)(x – 12) = 0
Taking,
⇒ (x – 11) = 0 or (x – 12) = 0
⇒ x = 11 or 12
From II,
y2 = (∛216)2
⇒ y2 = 36
⇒ y = 6 and -6
Comparison between x and y (via Tabulation):
Value of x
|
Value of y
|
Relation
|
11
|
6
|
x > y
|
12
|
6
|
x > y
|
11 |
-6 |
x > y |
12 |
-6 |
x > y |
∴ x > y.