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In a mixture of milk and water of 40 litres water is 5%. The amount of water (in litres) to be added to this mixture so as to make water 10% is
1. \(5\frac{1}{9}\)
2. \(3\frac{1}{3}\)
3. \(2\frac{2}{9}\)
4. \(6\frac{1}{9}\)

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Correct Answer - Option 3 : \(2\frac{2}{9}\)

Calculation:

5% of 40 liters

⇒ 5/100 × 40

⇒ 2 liters

In total mixture, 

Out of 40 liters, water is 2 liters.

⇒ Milk = 40 – 2 = 38 liters

Now when water is 10% then milk will be 90%

According to the question,

⇒ 90% = 38 liters

⇒ 10% = 38/9 liters

Increased quantity of water,

⇒ 38/9 – 2 = (38 – 18)/9

⇒ 20/9

⇒ \(2\frac{2}{9}\)

∴ The amount of water that needs to be added is \(2\frac{2}{9}\)liters.

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