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The modulation index of an AM modulated signal is 0.7 and the carrier power is 71.14 W. Calculate total sideband power.
1. 18.47 W
2. 23.14 W
3. 12.39 W
4. 17.43 W

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Correct Answer - Option 4 : 17.43 W

Concept:

The power of a transmitted AM wave is given as:

\(P_t = {P_c}\left( {1 + \frac{{{μ ^2}}}{2}} \right)\)

\(P_t = {P_c} + P_c\frac{μ ^2}{2}\)

Power in the carrier = Pc

Power in both the sidebands is given by:

\(P_s= \frac{{{P_c}{μ^2}}}{2}\)

Calculation:

Given:

μ = 0.7

Pc = 71.14 W

\(P_s= \frac{{{P_c}{μ^2}}}{2}\)

\(P_s= \frac{{{71.14} \ \times \ 0.7{^2}}}{2}\)

Ps = 17.43 W

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