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A is 30% more efficient than B and C is 20% more efficient than B. Working together, they can finish a work in 5 days. In how many days will A alone complete 3/5th of the total work?


1. 90/13 days
2. 105/13 days
3. 100/13 days
4. 110/13 days

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Correct Answer - Option 2 : 105/13 days

Given:

A is 30% more efficient than B.

C is 20% more efficient than B.

Concept used:

Total Work = Efficiency × Time

Calculation:

Let the efficiency of B be 100.

Efficiency ratio,

A ∶ B = 130 ∶ 100      ---(1)

B ∶ C = 100 ∶ 120      ---(2)

From equation (1) and (2), we get

A ∶ B ∶ C = 130 ∶ 100 ∶ 120

A ∶ B ∶ C = 13 ∶ 10 ∶ 12

Total Work = Efficiency × Time

Total Work = (13 + 10 + 12) × 5 = 35 × 5 = 175

TimeA = [3/4th of the total work]/Efficiency of A

TimeA = {(3/5) × 175}/13

TimeA = 105/13 day

∴ 'A' alone complete 3/5th of the total work in 105/13 days.

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