Question

Two buckets of same quantity are respectively (1/3)^rd and (2/5)^th full of milk. Then Ramesh filled up them with water and the contents are mixed in another bucket. What will be the new ratio of milk and water in another bucket?

1. 11 : 20
2. 12 : 25
3. 11 : 19
4. 12 : 11
5. 9 : 11

Answer 1

Correct Answer - Option 3 : 11 : 19

Given 

Part of milk in the first and second bucket respectively = (1/3)^rd and (2/5)^th

Formula used

Quantity of cheaper / Quantity of dearer = (Price of dearer - Average price) / (Average price - Price of cheaper)

Calculation

Part of water in first bucket = 1 – (1/3) = 2/3

Part of water in second bucket = 1 – (2/5) = 3/5

Part of milk in final mixture= (1/3) + (2/5) = 11/15

Part of water in final mixture= (2/3) + (3/5) = 19/15

Required ratio of mil and water in new bucket = (11/15) : (19/15) = 11 : 19

∴ The required ratio is 11 : 19.