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What is the least number which divided by 21, 28, 36, and 45, leaves remainder 4 in each case and is divisible by 13?
1. 5070
2. 4940
3. 5044
4. 4966

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Correct Answer - Option 3 : 5044

Given:

The number when divided by 21, 28, 36, and 45 and leaves the same remainder 4.

The number is also divisible by 13.

Calculations:

The least number which will be completely divisible by the 21, 28, 36, and 45 will be the LCM of 21, 28, 36, and 45

LCM(21, 28, 36, 45) = 1260

The least number will be completely divisible by the 21, 28, 36, and 45 and leaves remainder 4 = 1260k + 4

Where,

k = natural number

when k = 1

⇒ 1265

Here 1265 is not divisible by 13.

When k = 1, 2, 3, 4, 5. The number is not divisible by 13.

Now, k = 4

Number = 1260 × 4 + 4

⇒ Number = 5044

The number 5044 is divisible by 13

 

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