Correct Answer - Option 3 : 600
Given:
In a solution of alcohol and water having 40% alcohol, 220 litres of alcohol is further added such that the quanitiy of alcohol in the final solution is now 20 litres more than the quantity of
water.
Formula:
Final percentage of a quantity X = (Initial volume of X + added amount of X)/(Initial total volume + added amount)
Calculation:
Let the initial quantity of soluiton be x litres.
Quantity of alcohol = 0.4x
Quantity of water = 0.6x
After 220 litres of alcohol is added,
0.4x + 220 = 20 + 0.6x
⇒ 0.2x = 200
⇒ x = 1000
Quantity of water = 0.6x = 600 litres.