Correct Answer - Option 2 : 4 and 6
Given:
The ratio of the number of sides of two polygons is 2 : 3
And, the ratio between their interior angles is 1 ∶ 2.
Formula used:
Sum of interior angles of a polygon of sides n = (n - 2) × 180°
Calculation:
Let the number of sides of given polygons be 2n and 3n respectively.
Now, ATQ
(2n - 2) × 180°:(3n - 2) × 180° = 1 : 2
⇒ (2n - 2) : (3n - 2) = 1:2
⇒ 4n - 4 = 3n - 2
⇒ 4n - 3n = 4 - 2
⇒ n = 2
⇒ 2n = 4 and 3n = 6
∴ The total number of sides in given polygons is 4 and 6.