Correct Answer - Option 1 : 30 kN

**Concept:**

Stress:

The internal restoring force acting per unit area of the cross-section of the deformed body is called stress.

\(\rm Stress=\dfrac{Applied\;Force }{Area}=\dfrac{F}{A}\)

Its unit is N/mm2 Or MPa.

**Calculation:**

**Given:**

A = 50 mm^{2}, σ_{1} = 200 N/mm2, σ_{2} = 400 N/mm2.

\(\rm Stress=\dfrac{Applied\;Force }{Area}=\dfrac{F}{A}\)

∴ Force = Stress × Area

F1 = σ1 × A = 200 × 50 = 10000 N

F1 = 10000 N = 10 kN

F2 = σ2 × A = 400 × 50 = 20000 N** **

F2 = 20000 N = 20 kN

∴ Total Load, F = F1 + F2 = 10 + 20 = 30

Thus, Total Load = 30 kN.