Correct Answer - Option 1 : 30 kN
Concept:
Stress:
The internal restoring force acting per unit area of the cross-section of the deformed body is called stress.
\(\rm Stress=\dfrac{Applied\;Force }{Area}=\dfrac{F}{A}\)
Its unit is N/mm2 Or MPa.
Calculation:
Given:
A = 50 mm2, σ1 = 200 N/mm2, σ2 = 400 N/mm2.
\(\rm Stress=\dfrac{Applied\;Force }{Area}=\dfrac{F}{A}\)
∴ Force = Stress × Area
F1 = σ1 × A = 200 × 50 = 10000 N
F1 = 10000 N = 10 kN
F2 = σ2 × A = 400 × 50 = 20000 N
F2 = 20000 N = 20 kN
∴ Total Load, F = F1 + F2 = 10 + 20 = 30
Thus, Total Load = 30 kN.