Correct Answer - Option 1 : 0.75 m
Concept:
Equations of Motion
The following three equations are considered under motion in a straight line when there is a uniform acceleration.
v = u + at -- (1)
\(s = ut + \frac{1}{2}at^2\) -- (2)
v2 = u2 + 2ah -- (3)
s = u + a (n - ½) --(4)
u is initial velocity, v is final velocity, a is acceleration, t is the time interval, s is the travelled distance, n is the distance travelled in nth sec.
Calculation:
Given: u = 54 km/hr = 15 m/s, v = 0 m / s, t = 10 s.
From the equation:
v = u + at
0 = 15 + a × 10
a = - 1.5 m/s2
From the travelled distance in nth sec formula:
s = u + a (n - ½)
s = 15 - 1.5 (10 - ½)
s = 0.75 m