Correct Answer - Option 4 :
E = 2G (1 + μ)
Explanation:
E = Young's Modulus of Rigidity = \(\frac{Stress}{Strain}\)
G = Shear Modulus or Modulus of rigidity = \(\frac{Shear ~stress}{Shear~ strain}\)
μ = Poisson’s ratio = \(-\frac{Lateral~ strain}{Longitudinal~ strain} \)
K = Bulk Modulus of elasticity = \(\frac{Volumetric ~stress}{Volumetric ~strain}\)
Relation between E, K and μ
- E = 2G (1 + μ)
- E = 3K (1 - 2μ)
Combining the two above we get the relation between E, G and K
\(\mathbf{E~=~\frac{9KG}{G~+~3K}}\)