Correct Answer - Option 1 : 1
Concept:
The frequency of any class interval is calculated by subtracting the preceding cumulative frequency from the cumulative frequency of that class interval.
Calculation:
Marks obtained |
Number of students (c.f.) |
Frequency |
0 - 10 |
3 |
3 |
10 - 20 |
7 |
7 - 3 = 5
|
20 - 30 |
13 |
13 - 7 = 6
|
30 - 40 |
16 |
16 - 13 = 3
|
40 - 50 |
21 |
21 - 16 = 5
|
50 - 60 |
27 |
27 - 21 = 6
|
Now, the frequency of class interval 20 - 30 is p
⇒ p = 6
Also, the frequency of class interval 40 - 50 is q
⇒ q = 5
∴ p - q = 6 - 5 = 1
Hence, the difference of p and q is 1.