Correct Answer - Option 1 : x > y
Given:
I. 5x2 + 26x + 33 = 0
II. y2 + 18y + 65 = 0
Calculation:
From I,
5x2 + 26x + 33 = 0
⇒ 5x2 + 15x + 11x + 33 = 0
⇒ 5x(x + 3) + 11(x + 3) = 0
⇒ (x + 3)(5x + 11) = 0
Taking,
⇒ (x + 3) = 0 or (5x + 11) = 0
⇒ x = -3 or (-11/5)
From II,
y2 + 18y + 65 = 0
⇒ y2 + 13y + 5y + 65 = 0
⇒ y(y + 13) + 5(y + 13) = 0
⇒ (y + 13)(y + 5) = 0
Taking,
⇒ (y + 13) = 0 or (y + 5) = 0
⇒ y = -13 or -5
Comparison between x and y (via Tabulation):
Value of x
|
Value of y
|
Relation
|
-3
|
-13
|
x > y
|
-3
|
-5
|
x > y
|
-11/5
|
-13
|
x > y
|
-11/5
|
-5
|
x > y
|
∴ x > y.