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Ages of two persons differ by 16 years. If 6 year ago, the elder one be 3 times as old the younger one, find their present age?
1. 18, 34
2. 12, 28
3. 16, 32
4. 14, 30

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Correct Answer - Option 4 : 14, 30

Given:

Difference between two person ages = 16 years

Calculation:

Let the age of an younger person be A

age of elder person = (A + 16)

According to the question, we have

 3(A - 6) = (A + 16 - 6)

⇒ 3A - 18 = A + 10

⇒ 2A = 28

⇒ A = 14

∴ The younger and elder person age is 14 years old and 30 years old.   

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