Correct Answer - Option 2 : 200
Concept:
The efficiency of the heat engine
\(η_{HE} = 1-\frac{Q_L}{Q_H}\)
Where QL is heat rejected to the sink, QH is heat received from the source
Carnot heat engine efficiency
\(η = 1-\frac{T_L}{T_H}\)
Where TL is sink temperature, TH is Source temperature
Calculation:
Given:
QH = 600 kJ, TH = 627 °C = 627 + 273 = 900 K, TL = 27 °C + 273 = 300 K
Since the above engine is working on the carnot cycle, Therefore,
Carnot efficiency = Heat engine efficiency
η = ηHE
\(1-\frac{T_L}{T_H} = 1-\frac{Q_L}{Q_H}\)
\(\frac{300}{900} = \frac{Q_L}{600}\)
∴ QL = 200 kJ.
