Answer:
The angular frequency ω of the body
= 2π s–1
and its time period T = 1 s.
At t = 0 s
(a) Displacement = (5.0 m) cos [(2π s–1)*0 s + π/4]
= (5.0 m) cos [(π/4)]
= 5.0 x 0.70 m
= 3.5 m
(b) The speed of the body
= – (5.0 m)(2π s–1) sin [(2π s–1) *0 s+ π/4]
= – (5.0 m) (2π s–1) sin [(π/4)]
= -10π (0.707) m s–1
= -22 m s–1
(c) The acceleration of the body
= – (2π s–1)2 displacement
= – (2π s-1)2 (3.535 m)
= -140 m s–2