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Answer:

The angular frequency ω of the body

= 2π s–1

and its time period T = 1 s.

At t = 0 s

(a) Displacement = (5.0 m) cos [(2π s–1)*0 s + π/4]

= (5.0 m) cos [(π/4)]

= 5.0 x 0.70 m

= 3.5 m

(b) The speed of the body

= – (5.0 m)(2π s–1) sin [(2π s–1) *0 s+ π/4]

= – (5.0 m) (2π s–1) sin [(π/4)]

 = -10π (0.707) m s–1

 = -22 m s–1

(c) The acceleration of the body

= – (2π s–1)displacement

 = – (2π s-1)2 (3.535 m)

 = -140 m s–2

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