Question

Four resistances of 2.0Ω each are joined end to end to form a square A B C D. Calculate the equivalent resistance of the combination between any two adjacent corners.

 

Answer 1

Resistors R₁, R₂ and R₃ are in series, therefore their equivalent resistance is Rs = R₁ + R₂ + R₃= 2 + 2 + 2 = 6ohm.

Now R_s and R₄ are in parallel, therefore equivalent resistance of the combination between two adjacent corners is 

1/R_p = 1/R_s + 1/R₄ = 1/6 + 1/2 = 2/3 

Therefore R_p = 1.5ohm.