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What will be the co-channel reuse ratio for a system where i = j = 2?
1. 1
2. 6
3. 8
4. 3

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Correct Answer - Option 2 : 6

Concept:

In order to tessellate—to connect without gaps between adjacent cells—the geometry of hexagons is such that the number of cells per cluster, N, can only have values that satisfy Equation

N = i2 + ij + j2

The parameter Q, called the co-channel reuse ratio, is related to the cluster size.

For a hexagonal geometry 

\(Q=\frac{D}{R} = \sqrt {3N}\)

R: radius of the cell 

D: distance between centers of the nearest co-channel cells 

Calculation:

Given i = j = 2.

The cluster size is:

N = 22 + 2 × 2 + 22 

N = 12

The co-channel reuse ratio is:

\(Q=\sqrt {3\times 12} = \sqrt {36}\)

Q = 6

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