Correct Answer - Option 4 : 150
Concept:
nth term of A.P are a, a + d , a + 2d, . . . . ,a + (n - 1)d .
Tn = a + ( n - 1 ) d
Where a = first term and d = common difference
Calculation:
Three-digit numbers that are divisible by 6 are 102, 108, 114,... 996.
The series of AP is 102, 108, 114,... 996.
As we know that , Tn = a + ( n - 1 ) d
⇒ 996 = 102 + ( n - 1 ) 6
⇒ 894 = ( n- 1 ) 6
⇒ 149 = n - 1
⇒ n = 150
The correct option is 4
