Question

Three resistors are connected to a 12V battery as shown in the figure given below :

1. What is the current through the 8Q resistor? 

2. What is the potential difference across parallel combination of 6Q and 12Q? 

3. What is the current through the 6Q resistor?

Answer 1

r₂ , r₃ are in parallel 

1/R_p = 1/12 +1/6 = 3/12 = 1/4 

R_p = 4r₁ and R_p are in series 

:. R = r₁ + r = 8 + 4 = 12Ω 

1. I = v/R = 12/12 = IA 

2. P.D across parallel combination AB 

V = IRp 

I × 4 = 4V 

3. Current through 6Ω 

I = v/r₃ = 4/6 = 0.666 

I = 0.67A