Correct Answer - Option 4 : 50 kW

**Concept:**

The output power of a three phase synchronous motor is given by

\(P = \frac{{3EV}}{{{X_s}}}\sinδ \)

P = output power of the synchronous motor

E = generated e.m.f per phase

V = terminal voltage per phase

X_{S} = synchronous reactance per phase

δ = load angle

**Calculation:**

__Given:__

E = 400, V = 250 V, X_{S} = 1 Ω, δ = 30°

The output power of synchronous motor per phase

\(P = \frac{{EV}}{{{X_S}}}\sinδ = \frac{{250\; \times 400\;}}{{1\;}} \times \sin30^\circ \)

**P = 50 kW**