Correct Answer - Option 4 : 50 kW
Concept:
The output power of a three phase synchronous motor is given by
\(P = \frac{{3EV}}{{{X_s}}}\sinδ \)
P = output power of the synchronous motor
E = generated e.m.f per phase
V = terminal voltage per phase
XS = synchronous reactance per phase
δ = load angle
Calculation:
Given:
E = 400, V = 250 V, XS = 1 Ω, δ = 30°
The output power of synchronous motor per phase
\(P = \frac{{EV}}{{{X_S}}}\sinδ = \frac{{250\; \times 400\;}}{{1\;}} \times \sin30^\circ \)
P = 50 kW