Question

In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.

I. 5x2 + 17x - 12 = 0

II. 3y2 - 4y - 39 = 0

1. x > y
2. x < y
3. x ≥ y
4. x ≤ y
5. x = y or relation between x and y can not be established.

Answer 1

Correct Answer - Option 5 : x = y or relation between x and y can not be established.

Given:

I. 5x² + 17x - 12 = 0

II. 3y² - 4y - 39 = 0

Calculation:

From I,

5x² + 17x - 12 = 0

⇒ 5x² + 20x - 3x - 12 = 0

⇒ 5x(x + 4) - 3(x + 4) = 0

⇒ (x + 4)(5x - 3) = 0

Taking,

⇒ (x + 4) = 0 or (5x - 3) = 0

⇒ x = -4 or (3/5)

From II,

3y² - 4y - 39 = 0

⇒ 3y² - 13y + 9y - 39 = 0

⇒ y(3y - 13) + 3(3y - 13) = 0

⇒ (3y - 13)(y + 3) = 0

Taking,

⇒ (3y - 13) = 0 or (y + 3) = 0

⇒ y = (13/3) or -3

Comparison between x and y (via Tabulation):

Value of x	Value of y	Relation
-4	13/3	x < y
-4	-3	x < y
3/5	13/3	x < y
3/5	-3	x > y

∴ x = y or relation between x and y can not be established.