Correct Answer - Option 3 : 0.04
Concept:
The coefficient of detention is given by:
\(\frac{{Friction\;force\;at\;sleeve}}{{Weight\;of\;ball + Weight \; of \; sleeve}}= \frac{f}{{(M+m)g}} \)
Calculation:
Given:
Weight of the sleeve = 200 N, ball weight = 50 N, Friction force (f) = 10 N.
The coefficient of detention will be
Coefficient of detention \(= \frac{{10}}{{(200+50)}}\)
Coefficient of detention = 0.04