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The sleeve and each rotating mass of a Porter governor weigh respectively, 200 N and 50 N. If the friction at the sleeve is 10 N then the coefficient of detention would be:
1. 0.20
2. 0.40
3. 0.04
4. 0.05

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Correct Answer - Option 3 : 0.04

Concept:

The coefficient of detention is given by:

\(\frac{{Friction\;force\;at\;sleeve}}{{Weight\;of\;ball + Weight \; of \; sleeve}}= \frac{f}{{(M+m)g}} \)

Calculation:

Given:

Weight of the sleeve = 200 N, ball weight = 50 N, Friction force (f) = 10 N.

The coefficient of detention will be 

Coefficient of detention \(= \frac{{10}}{{(200+50)}}\)

Coefficient of detention = 0.04

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