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If the product of two fractions is \(\frac{14}{15}\) and their corresponding division is \(\frac{35}{24}\), then the largest fraction is
1. \(\frac{7}{4}\)
2. \(\frac{7}{6}\)
3. \(\frac{6}{7}\)
4. \(\frac{7}{8}\)

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Correct Answer - Option 2 : \(\frac{7}{6}\)


Let the two fractions be x and y.

⇒ xy = \(\frac{14}{15}\) and \(\frac{x}{y}=\frac{35}{24}\)

On multiplying both the conditions, we get

\(⇒ xy \times \frac{x}{y}=\frac{14}{15}\times \frac{35}{24}\)

⇒ x2 = 49/36

⇒ x = 7/6

∴ y = (14/15) ÷ (7/6)

⇒ y = 4/5

Clearly, from x and y, x is greater. 

Hence, 7/6 is greater fraction. 

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