Given that =2V, r = I.2Ω, RA = O.8Ω,R1 = 4.5Ω , R2=9Ω ]
1. We know that for the circuit = IR total
Now, the total resistance of the circuit is
R total = r + RA + Rp
1/Rp = 1/4.5 + 1/9 = 3/9
Rp = 3Ω
R total = 1.2 + 0.8 + 3 = 5Ω
Hence, the current through the ammeter is
I = V/Rtotal = 2/5 = 0.4A
(ii) I = (E - V)/r
⇒ 0.4 = (2 - V)/1.2
I = v/R total = 2/5 = 0.4 AB
⇒ 0.48 = 2 – V - I
V = 2 – 4.8 – 1.52V
:. Potential difference Vcell 1.52V