Question

In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.

I. x² – 4x - 77 = 0

II. y² + 23y + 132 = 0

1. x > y
2. x < y
3. x ≤ y
4. x ≥ y
5.

x = y or the relation between x and y can't be established.

Answer 1

Correct Answer - Option 1 : x > y

Given:

I. x² – 4x - 77 = 0

II. y² + 23y + 132 = 0

Calculation:

I. x² – 4x - 77 = 0

⇒ x² + 7x – 11x - 77 = 0

⇒ x(x + 7) - 11(x + 7) = 0

⇒ (x - 11)(x + 7) = 0

⇒ x = (-7), 11

II. y² + 23y + 132 = 0

⇒ y² + 12y + 11x + 132 = 0

⇒ y(y + 12) + 11(y + 12) = 0

⇒ y = (-12), (-11)

Value of ‘x’	Relation	Value of ‘y’
-7	>	-12
-7	>	-11
11	>	-12
11	>	-11

 

When we compared the values of ‘x’ and ‘y’ in the table above, we found that there is ONE relation between X and Y i.e. >. So, a relation between x and y is x > y.

∴ After comparison, all the values of x and y the relation is x > y.