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Find the value of: \(\frac{3^3~+~2^3~-~5^3}{9~\times~2~\times~5}\)

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Correct Answer - Option 3 : -1

Given:

The expression is 

\(\frac{3^3~+~2^3~-~5^3}{9~\times~2~\times~5}\)

Formula used:

a3 + b3 + c3 - 3abc = (a + b + c)(a2 + b2 + c2 - ab - bc - ca)

If a + b +c = 0 then a3 + b3 + c3 = 3abc

Calculation:

We have to find the value of 

\(\frac{3^3~+~2^3~-~5^3}{9~\times~2~\times~5}\)

⇒ \(\frac{(3)^3~+~(2)^3~+~(-5)^3}{3~\times~3~\times~2~\times~5}\) 

Here, 3 + 2 + (-5) = 0 so,

⇒ \(\frac{3~\times~3~\times~2~\times~(-5)}{9~\times~2~\times~5}\)

⇒ -1

∴ The value of the expression \(\frac{3^3~+~2^3~-~5^3}{9~\times~2~\times~5}\) is -1. 

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