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A car is accelerated on a levelled road and attains a speed 4 times of its initial speed. In the process the KE of car 
1. becomes 4 times of its initial KE
2. becomes 8 times of its initial KE
3. becomes 16 times of its initial KE
4. becomes 64 times its initial KE

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Correct Answer - Option 3 : becomes 16 times of its initial KE

Concept:

Kinetic Energy (K): 

The energy of the body in motion by virtue of motion is called kinetic energy.

\(K = \frac{1}{2}mv^2\)

m is the mass of the body, v is the speed of the body.

Calculation:

So, let the initial speed is u, and final speed is v

According to the question, v = 4u

Initial Kinetic Energy 

\(K = \frac{1}{2}mu^2\)

Final Kinetic Energy 

\(K' = \frac{1}{2}mv^2 = \frac{1}{2}m(4u)^2 = 16 (\frac{1}{2}mu^2)\)

⇒ \(K' = 16 K\)

So, the final kinetic energy is 16 times the initial KE.

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