Question

A sample of silty clay has a volume of 14.88 cm³, a total mass of 28.81 gm, a dry mass of 24.83 gm and a specific gravity of solids 2.7. What is the void ratio ?
1. 0.412
2. 0.521
3. 0.618
4. 0.663

Answer 1

Correct Answer - Option 3 : 0.618

Explanation:

Given,

Volume = 14.88 cm³, Total Mass = 28.82 gm, Dry mass = 24.83 gm

Specific Gravity G = 2.70, 

Bulk density \(\left( γ_b \right) = \frac{W}{V}\)

γ_b = 28.82/14.88 = 1.93 gm/cc 

Dry density, \({γ _d} = \frac{γ }{{1 + w}}\)

Water content formula is given by:

w = Ww/Ws

where, 

w = Water content, Ww = Weight of water, Ws = Weight of solids

Water content, \(w = \frac{{28.81 - 24.83}}{{24.83}} \times 100\% \)

= 16.02%

\(\begin{array}{l} \therefore {γ _d} = \frac{{1.93}}{{1 + 0.1602}} = 1.663g/{cm^3}\\ {γ _d} = \frac{{{γ _w}G}}{{1 + e}} \end{array}\)

⇒ e = 0.623