Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
211 views
in General by (114k points)
closed by
A fine grained soil is found to have a liquid limit of 90% and a plasticity index of 50. The natural water content is 28%. What is the liquidity index ?
1. -0.34
2. -0.14
3. -0.24
4. -2.40

1 Answer

0 votes
by (115k points)
selected by
 
Best answer
Correct Answer - Option 3 : -0.24

Concept:

The plasticity Index, Iof soil is given as:

IP = WL - Wp

The Liquidity Index, I is given as:

\(({I_L} = \frac{{{W_n} - \;{W_P}}}{{{W_L} - \;{W_P}}} = \frac{{{W_n} - \;{W_P}}}{{{I_P} }})\)

Where

WL is the liquid limit of soil

WP is the Plastic Limit of soil

⇒ IP is plasticity Index = Liquid Limit - Plastic Limit

Wn is water content of the soil under given conditions or natural water content

Calculation

Given: WL = 90%; IP = 50 %

Natural Water Content Wn = 28%

IP = WL - Wp ⇒ 50 = 90 – WpWp = 40 %

The Liquidity Index, I is calculated as:

\(({I_L} = \frac{{28 - \;40}}{{50}})\) = - 0.24

1. The Liquidity index of soil indicates its degree of consistency i.e. Higher the liquidity index, the more the soil will be consistent.

2. If IL ≥ 1, then soil is in liquid state.

3. If IL = 0, then the soil is in the plastic state.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...