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A soil has bulk density of 20.1 kN/m3 and water content 15%. What is the water content if the soil partially dries to a density of 19.4 kN/m3 and the void ratio remains unchanged ?
1. 10.86%
2. 10.76%
3. 10.68%
4. 10.66%

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Best answer
Correct Answer - Option 1 : 10.86%

Explanation:

Given,

Case - I: Bulk density = 20.1 kN/m3, water content = 15%

Case II: Dry Density = 19.4 kN/m⇒ water content = ??

No change in void ratio.

As, dry unit weight (γd) = γ/(1 + w)  

\(\begin{array}{l} {γ_d} = \frac{γ}{{1 + w}} = \frac{{20.1}}{{1 + 0.15}} = 17.478\; kN/{m^3}\\ {γ_d} = \frac{{{γ_w}.G}}{{1 + e}} \end{array}\)

 If void ratio 'e' remains unchanged during drying,  \(γ_d\)  also remains unchanged. 

\(\begin{array}{l} {γ_d} = \frac{γ}{{1 + w}}\\ 17.478 = \frac{{19.4}}{{1 + w}} \end{array}\)

w = 10.99 %

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