Correct Answer - Option 1 : 3

**Given**

[2 + sec2A - cot2(90° - A)] × [tan2(90° - A) × (1/cot 2A)]

**Formula used**

cot(90° - A) = tan A

tan(90° - A) = cot A

**Calculation**

[2 + sec2A - cot2(90° - A)] × [tan2(90° - A) × (1/cot 2A)]

= [2 + sec^{2}A - tan ^{2}A] × (cot ^{2}A) × (1/cot ^{2}A)

⇒ (2 + 1) × 1

⇒ 3 × 1

⇒ 3

**∴ [2 + sec2A - cot2(90**°** - A)] × [tan2(90**°** - A) × (1/cot 2A)] is 3**