Correct Answer - Option 3 : 11.9 calories

**Concept of conversion of Joule to calories:**

- S.I unit of both Heat and Energy is the same i.e., Joule.
- The CGS (Centimeter, Gram, Second) unit of Heat is calories.
- 1 Calorie = 4.186 Joule.

We know that Energy stored by a capacitor is given by,

\({E_C} = \frac{1}{2}C{V^2}\) Joule

\(H = \frac{{{E}}}{{4.186}}\) Calorie

Where H is Heat produced, E is Energy.

**Calculation:**

Given: C = 1 microfarad, V_{C} = 10kv

As per the formula,

\({E_C} = \frac{1}{2}C{V^2}\) Joule

\({E_C} = \frac{1}{2} \times \left( {1 \times {{10}^{ - 6}}} \right) \times {\left( {10 \times {{10}^3}} \right)^2}\)

E_{C} = 50 Joule

\(H = \frac{{{E_C}}}{{4.186}}\) Calorie

\(H = \frac{{50}}{{4.186}} = 11.9\;\) Calorie