Correct Answer - Option 1 :
\(2{2 \over {17}}\) hours
Given:
Pipe A can fill a cistern in 3 hours
Pipe B can fill a cistern in 4 hours
Pipe C can empty a cistern in 9 hours
Formula:
(A + B + C)’s 1 hour work = 1/A + 1/B – 1/C
Calculation:
Part of the tank filled in one hour =1/3 + 1/4 −1/9
⇒ 7/12 – 1/9
⇒ 17/36 part of the tank is filled
the tank is filled in = 36/17 hours = \(2{\textstyle{2 \over {17}}}\) hours.
∴ The tank is filled in \(2{\textstyle{2 \over {17}}}\) hours.